For tha configuraton shawn in tha figure below, suppose \"-5.00 cm, b-20.0 cm, a

Question

For tha configuraton shawn in tha figure below, suppose "-5.00 cm, b-20.0 cm, and c-25.0 cm. Furthermore, suppose the alactric field at paint 14.5 cm fram the center is measured tn b 3.55 x 1o2 N/C r dially nward and the elactric feld t a point 5.0 cm from the center is of magnitude 198 NC and points raialy outward. From this intormation, tind the following(nclude the sign of the charge in your answer) Insulator a) the charga an tha insating phare the net charga on tha hallow c phere )the charga on tha innar aurfacs of the hellow concucting sphera (d) the charge on the cuter curface of the hallaw g sphcre

Explanation / Answer

from Gauss law,

net flux = E ( 4 pi r^2) = Qin / e0

(A) for r = 14.5 cm = 0.145 m

E = -3.55 x 10^3 N/C

and Qin = Qa

(4 x pi x 0.145^2) (-3.55 x 10^3) = Qa / (8.854 x 10^-12)

Qa = - 8.30 x 10^-9 C ....Ans

(B) r = 50 cm , E = 198 N/C

Qin = Qa + Q

(198)(4 x pi x 0.50^2) = (Qa + Q) / (8.854 x 10^-12)

Q = +13.8 x 10^-9 C

(C) for b < r < C , E = 0

so Qin = 0

Qin = Qa + Qb = 0

Qb = - Qa = 8.30 x 10^-9 C

(D) Qb +Qc = Q

Qc = Qc - Qb = 5.50 x 10^-9 C

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