Two different gene loci are responsible for determining mouse coat color. A rece

Question

Two different gene loci are responsible for determining mouse coat color. A recessive lethal allele contributing to yellow coat color also exists for one of these two gene loci. The following genotypic and phenotypic information about the mouse coat color alleles is known 9. Agouti A-B- . Yellow = AAB-or AaB. or Arab. . Lethal (inviable zygote) AA- . Black=aa& Albino-bb A cross is made that produces 2 yellow, 1 black, and 3 albino mice. What are the genotypes and phenotypes of each of the parents? a. A cross between the black offspring and one of its yellow siblings produces 2 albino, 1 black, and 1 yellow offspring.What is the genotype of the yellow parent? b.

Explanation / Answer

Answer a.) Since the offsprings are (with their possible genotypes):

2 Yellow- AAyB_/AyaB_/Ayab_

1 Black- aaB_

3 Albino- __bb

***The _ represents either dominant or recessive.

Since there is a yellow offspring, one of the parents should be yellow(Ay), black offspring means both parents should have atleast 1 a allele & 1 parent should have one B allele and albino means both the parents shoula have atleast 1 b allele

Thus the genotypes of the parents are

AyaBb (Yellow) X _abb (Albino)

Answer b) 2 albino- Both parents should have atleast 1 b allele,

1 black- Both parents should have atleast 1 a allele and one of the parents should have one B allele and

1 yellow - one of the parents should have one Ay allele

Thus the genotypes of the parents are:

aaBb (Black) X Ayab_ (Yellow)

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