Question 22 of 36 Sapling Learning Map For a single, isolated point charge carry

Question

Question 22 of 36 Sapling Learning Map For a single, isolated point charge carrying a charge of q = 5.22 x 10" C, one equipotential surface consists of a sphere of radius 0.0154 m centered on the point charge as shown. What is the potential on this surface? Number 40.0154 m You would like to draw an additional equipotential surface, which is separated by 10.2 V from the previously mentioned surface. How far from the point charge should this surface be? This surface must also meet the condition of being farther from the point charge than the original equipotential surface Number

Explanation / Answer

a] Potential V = kq/r = 9e9*5.22e-11/0.0154 = 30.5 V answer

b] For being farther, potential should be smaller, 30.5-10.2 = 20.3 V

r = kq/V = 9e9*5.22e-11/20.3 = 0.0231 m answer

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