1. A diffraction pattern created by a slit of width 0.3 mm on a screen 1.5 m fro
ID: 1871073 • Letter: 1
Question
1. A diffraction pattern created by a slit of width 0.3 mm on a screen 1.5 m from the slit is 5.0 mm 2.5 mm 0 mm What is the wavelength of light used to create this diffraction pattern? a. b. What is the width of the central maximum of this diffraction pattern? If the slit width is doubled, what will the width of the central maximum be? c. If the slit width is one-third of its original value, what will the width of the central maximum be? d. e. If the wavelength of the light is 400 nm, what will the width of the central maximum be?Explanation / Answer
1. (A) for m = 1
y = 2.5 mm = 2.5 x 10^-3 m ( for dark fringe)
y = (m -0.5) lambda D / a
2.5 x 10^-3 = 0.5 x lambda x 1.5/ (0.3 x 10^-3)
lambda = 1 x 10^-6 m
(B) width = 5 mm
(C) slit width is doubled then
width of central is halved.
= 2.5 mm
(D) w = 3 x 5 = 15 mm
(E) y = lamdba D / a
= (400 x 10^-9) (1.5) / (0.3 x 10^-3)
= 2 x 10^-3 m or 2 mm
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