Number 1 and 2 please. 1. Question Details SerCP8 15.P.026. My Notes Ask Your Te

Question

Number 1 and 2 please.

1. Question Details SerCP8 15.P.026. My Notes Ask Your Teacher Two point charges lie along the y-axis. A charge of q1 -8.5 pC is at y 6.0 m, and a charge of q2 =-5.5 pC is at y =-4.0 m. Locate the point (other than infinity) at which the total electric field is zero. 2.65 Need Help? Talk to a Tuter Show My Work (optional) Submit Answer Save Progress Practice Another Version 2. Question Details SerCP8 15.P020.soln. My Notes Ask Your Teacher An electron is accelerated by a constant electric field of magnitude 305 N/C (a) Find the acceleration of the electron. m/s2 (b) Use the equations of motion with constant acceleration to find the electron's speed after 1.25 × 10-8 s, assuming it starts from rest. m/s Need Help? Read.] Lintentorl

Explanation / Answer

1. field will be zero at point in between the charges.

E = k (8.5) / d^2 - k (5.5 uC) / (10 - d)^2 = 0

d / (10 - d) = sqrt(8.5 / 5.5) = 1.243

d = 5.54

y = 6 -5.54 = 0.46 m ......Ans

2. (A) a= Fe / m = q E / m

a = (1.602 x 10^-19)(305) / (9.109 x 10^-31)

a= 5.364 x 10^13 m/s^2

(B) v= v0 + a t

v = 0- + (5.364 x 10^13)(1.2 x 10^-8)

v = 6.44 x 10^5 m./s

Related Questions

Navigate

• Browse (All)
• Browse N
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.