A, B ,C please. For part A, there is no Q to use for the equation, also it gave

Question

A, B ,C please. For part A, there is no Q to use for the equation, also it gave me a hint for part A

(1496) Problem 5: As part of the design process for a new transistor, an engineer uses a vacuum chamber to bombard a thin layer of silicon with ions of phosphorus, each of mass mp = 5.18 x 10-26 kg. The phosphorus ions are doubly ionized, with each phosphorus ion lacking two electrons. The ions start at rest at one end of the vacuum chamber and are accelerated by an electric field over a distance of re = 33 cm before they strike the silicon layer with velocity vp = 185 m/s Randomized Variables re -33 cm vp= 185 m/s 33% Part (a) Enter an expression for the potential difference V, in volts, between the initial and final points across the vacuum chamber Grade Summary Deductions Potential 4% 96% Submissions Attempts remaining: 8 % per attempt) detailed view 2% 2% Tm END BACKSPACE DELCLEAR Submit Hint I give up! Hints: 1 for a 0% deduction. Hints remaining: 2 Feedback: 0% deduction per feedback. Each phosphorus ion is missing two electrons, so the electric charge on each ion is +2*(1.602 x 1019 c) 33% Part (b) Calculate the average electric field strength E, in volts per meters, across the vacuum chamber 33% Part (c) Calculate the average electric force F, in newtons, that the electric field exerts on each phosphorus ions

Explanation / Answer

(a) delta(KE) = q deltaV

mp vp^2/ 2 = (2e) deltaV

deltaV = mp vp^2 / (4 e)

(B) E = deltaV / d

= mp vp^2 / (4 e re)

putting values,

E =8.39 x 10^-3 V/m Or N/C

(c) F = q E = 2.686 x 10^-21 N

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