15il gnment.aspx Chapter 21 Begin Date: 252018 1:00:00 AM-Due Date: 2/11/2018 11

Question

15il gnment.aspx Chapter 21 Begin Date: 252018 1:00:00 AM-Due Date: 2/11/2018 11:55:00 PM End Date: 2/12/2018 11:55 00 PM (13%) Problem 2: A power line carries a DC current of1-23 A in a direction -43° east of magnetic north through an open field, in a location where the Earth's magnetic field is horizontal and its strength is B- 0.37G A 17% Part (a) Calculate Earth's magnetic field the magnitude of the magnetic force per unit length, F/I, in ma per meter, exerted on the wire due to the us Grade Summary Potential 100% pleted cos0 cotan0 asinacos0 atan() | acotanol sinh0- 1|2|- Atempts remaiming (1% per attempt) Hint Hints:-deduction per hit. Hints tem Feedback:deduction per 17% Part (b) In what direction does the force on the wire act? 17% Part (c) You decide to re-onent the wire to minimize the magnetic force acting on the wire. In what direction(s) could the current flow? 17% Part (d) In what direction(s) could you orient the current now to maximize the magnetic force acting on the wire? 17% Part (e) In ntuch of the directions that correctly ansmer part (d) is the magnetic force on the wire up? w 17% Part

Explanation / Answer

I r^ = 23A x 1m (sin43i - cos43j)

= 15.69 i - 16.82 j

B = 0.37 x 10^-4 j

(A) F / L = Ir^ x B  

= 5.81 x 10^-4 N

(B) upward  

(C) current have to flow in the direction of magnetic field.

magnetic north.

(D) perpendicular to the field.

to the east or to the west  

(E) to the east

(F) F/L = 23 x 0.37 x 10^-4 = 8.51 x 10^-4 N/ m

8.51 x 10^-4 / 9.81 = m

m = 8.67 x 10^-5 kg / m

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