(A) Find the acceleration of the electron while it is in the electric field. whi

Question

(A) Find the acceleration of the electron while it is in the electric field.
which is -3.6531e13
(B) Assuming the electron enters the field at time t = 0, find the time at which it leaves the field.

which is 3.33e-8 seconds
(C) Assuming the vertical position of the electron as it enters the field is yi = 0 what is its vertical position when it leaves the field?

Categorize Because the electric force is constant in the figure, the motion of the particle in the vertical direction can be analyzed by modeling it as a particle under constant acceleration.

Describe the position of the particle at any time t:

yf = yi + vyit + ½ ayt2

Substitute numerical values:

yf = 0 + 0 + ½at2 =

Find the C)what is vertical position when it leaves the field?

If the electron enters just below the negative plate in the figure and the separation between the plates is less than the value just calculated, the electron will strike the positive plate. We have neglected the gravitational force acting on the electron, which represents a good approximation when dealing with atomic particles. For an electric field of 200 N/C, the ratio of the magnitude of the electric force eE to the magnitude of the gravitational force mg is on the order of 1012 for an electron and on the order of 109 for a proton.

And D) find the speed of the electron as it emerges from the field.

and can you solve C and D please

(C) Assuming the vertical positlon of the electron as It enters the field Is y-0 what is its vertical pouition when It leaves the fleld? Catogortzo Because the electric force Is constant in the figure, the motion of the partide in the vertical direction can be analyzed by modeling It as a particle under constant acceleration. Describe the position of the particle at anyXtt h af tme t: Substitute numerical values: the electron enters just below the negative plate in the ftigure and the separation between the plates s less than the value just calculated, the electron will strike the positive plate. We have neglected the gravitational force acting on the electron, which represents a good approximation when dealing with atomic particles. For an electric field of 200 N/C, the ratio of the magnitude of the electric force eE to the magnitude of the gravitational force mg is on the order of 1012 for an electron and on the order of 10 for a proton HINTS: GETTING STARTED 1 IM STUCK MASTER IT Find the speed of the electron as it emerges from the field. X m/s over the time the Speed = 3.611006 Determine the extra component of velocity ca particle passes between the plates. Use that to find the speed used by the electric field foroe ls to a Tutor

Explanation / Answer

According to the concept of the electric field and charges

Given that

Electric field E=208 N/c

Initial velocity u=3*10^6 m/s

Charge q=1.6*10^-19 C

Mass m=9.1*10^-31 kg

Now we find the vertical position electron leaves the field

Vertical position y=ut+1/2(qE/m)t^2

=0+0.5*(1.6*10^-19*208/9.1*10^-31)*(3.33*10^-8)^2

=202.8*10^-4

=2.03 cm

Now we find the speed of the electron after field emerges

Speed V=(u^2+2gy)^1/2

=[(3*10^6)^2+2*9.8*2.03*10^-2]^1/2

=[9*10^12+0.39788]^1/2

=3*10^6 m/s

  

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