ework: 2.B Motion Begin Date: 1131/2018 12:00:00 AM-Due Date: 2/7/2018 11:59.00

Question

ework: 2.B Motion Begin Date: 1131/2018 12:00:00 AM-Due Date: 2/7/2018 11:59.00 PM End Date: 2/14/2018 11-59.00 PM 11%) Problem 7: The cannon on a battleship can fire a shell a maximum distance of 395 km. 33% Part (a) Calculate the initial speed of the shell, in meters per second. Neglect air resistance to make the problem easier. @v 33% Part (b) what maximum height, in meters.does it reach? 33% Part (c) The ocean is not flat, because the Earth is curved. Take the radius of the Earth to be 638 x 103 km. How much lower, in meters, will its surface be 39 5 km from the ship as measured along a line that is tangent to the surface of the Earth at the location of the ship? Grade Summary Potential 100 Submissioes 7 8 9 sin cos tan cotan) asinacoso atan) acotansinh0 Attempts remaining 18 detailed ve °Degrees Radians I give up Hints: 0% deduction per hint Hints temaining: 4. Feedbacki 05 deduction per feedbck MacBook Air 888 a 5 7 8 9

Explanation / Answer

According to the concept of the motion in two dimensional

Maximum distance Rmax=u^2/g

Given that

Maximum distance Rmax=39.5 km=39.5*10^3 m

Now we find the initial speed of the shell

Initial speed u=(39.5*10^3*9.8)^1/2=622.2 m/s

Now we find the maximum height

Maximum height =u^2/2g

=622.2^2/2*9.8

=19751.7 m

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