d WileyPLUS //edugen.wileyplus.com/edugen/iti/main.uni Halliday, Fundamentals of

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d WileyPLUS //edugen.wileyplus.com/edugen/iti/main.uni Halliday, Fundamentals of Physics, 10e pRIN TER VERSION BACK Chapter 05, Problem 034 in the ioure, a crate of mass m -88 ko is oushed at a constant speed up a frictionles amp (e-262) by a horizontal force F.The positive direction of an x axis is up the ramp, positive direction of a y axis is perpendicular to the ramp. (a) What is the magnitude of F (b) what is the magn tude of the normal force on the crate? (a) Number Units (b) Number Units HOW HENT TUTORIAL LINK TO LINK TO SAMPLE PROBLEM VIDEO MINE-LECTURE SAMPLE

Explanation / Answer

a] Along x direction, the acceleration is zero and so the net force is zero.

So, Fcos26 - mgsin26 = 0

=> F = [mgsin26]/cos26 = mgtan26 = (88 x 9.8 tan26) = 420.62 N

b] Since the crate is not moving along y direction, the net force in y direction must also be zero.

=> R - Fsin26 - mgcos26 = 0

=> R = 959.51 N.

this is the normal reaction force.

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