1. The concrete structure shown below is an office building. The floor system of
ID: 1866938 • Letter: 1
Question
1. The concrete structure shown below is an office building. The floor system of the structure is supported by floor beams and girders as shown. Each concrete beam is 7 feet long with typical rectangular cross-sectional area of 48 in2. The concrete floor beams are 5 ft apart center-to-center. The thickness of the concrete slab is 4 inches. Determine and sketch the loading that acts along the concrete Girder 1. Girder 1 is 40 ft long and has a cross-sectional area of 216 in2. Consider a live load of 40 lb/ft2. The unit weight of concrete is 150 lb/ft3 (20 points) Girder 1Explanation / Answer
Answer:
Thickness of slab=4 in
Self Weight of slab=(4/12)*150=50 psf
Tributary width of girder=7/2=3.5 ft
Load on girder due to slab=50*3.5=175 plf
Self weight of girder=216*150/144=225 plf
Self weight of each beam=150*48/144=50 plf
Load on girder due to weight of each beam=50*3.5=175 lbs
Total number of beams supporrted by girder=7
Total load on girder due to Weight of beams=7*175=1225 lbs
Weight of girder=225*40=9000 lbs
Load on girder due to weight of slab=175*40=7000 lbs
Total dead load on girder=1225+9000+7000=17225 lbs
Total live load on girder=40*3.5*40=5600 lbs
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