Just answer PROBLEM 4 F-8 kip 10 in 5 in -5 in- 1.4 d in Figure 1 (Problems 3,4,

Question

Just answer PROBLEM 4

F-8 kip 10 in 5 in -5 in- 1.4 d in Figure 1 (Problems 3,4,5, 6 and 7) ID 0 Problem 3 For the loaded shaft shown above with d 3.0 inches calculate the nominal bending stress at the critical location (diameter change near center of shaft) Answer A) 14.6 ksi B) 5.58 ksi C) 20.2 ksi (D))7.55 ksi E) 4.10 ksi 3476i Problem4 If the shaft is machined from steel with Sy 45 ksi and Sut 60 ksi quantify the stress concentration factor at the critical location and determine the safety factor for yielding at this location.

Explanation / Answer

The critical section is the junction of 2 shafts so stress concentration will be there as there is change in diameter so,

Stress Concentration factor = (maximum stress at the section/ average stress at that section)

Maximum stress at junction =7.55

Average stress =(7.55+2.75)/2 = 5.15

So Kf= 7.55/5.15= 1.466.

Factor of safety = maximum stress/allowable stress

FOS= 45/7.55= 5.96

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