S: A negative charge ofq--13 x 10-17C and m - 83 x 1026 kg enters a magnetic fie
ID: 1866083 • Letter: S
Question
S: A negative charge ofq--13 x 10-17C and m - 83 x 1026 kg enters a magnetic field B-19T with initial velocity magnetic field points into the screen. v 510 m/s, as shown in the figure. The Randomized Variables 9-13x 10-17c m=8.3 × 10-26 kg B-19T v510 m/s ©theexpertta.com v 13% Part (a) which direction will the magnetic force be on the charge? ??13% Part (b) Express the magnitude of the magnetic force, F, in terms of q, v, and B. ??13% Part (c) Calculate the magnitude of the force F, in newtons. g e 13% Part (d) Under such a magnetic force, which kind of motion will the charge undergo? 13% Part (e) Express the centripetal acceleration of the particle in terms of the force F and the mass m. -?13% Part (D Calculate the magnitude of a, in meters per square second. ?d & 13% Part (g) Express the radius, R, of the circular motion in terms of the centripetal acceleration a and the speed ?? 13% Part (h) Calculate the numerical value of the radius R, in meters. . Grade Summary Potential 100%Explanation / Answer
B.
F= qvB
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C. F= 1.3*10^-17*510*1.9= 1.26*10^-14 N
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E.
Centripetal acceleration
a=F/m
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F.
a= 1.26*10^-14/(8.3*10^-26)
a= 1.52*10^11 m/s^2
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G.
a=v^2/r
r=V^2/a
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r= 510*510/(1.52*10^11)
r= 1.714*10^-6 m
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