Four light bulbs, each with resistance of 240, are connected in parallel and plu

Question

Four light bulbs, each with resistance of 240, are connected in parallel and plugged into a 120 volt outlet as shown below.
a. If any of the bulbs was removed, what would happen to the remaining bulbs (I.e. would the other bulbs remain lit?) explain
b. If any one of the bulbs was removed, would the brightness of the remaining bulbs increase, decrease or remain the same? Explain, and support your answer with calculations
c. If all four bulbs were now connected in series, would their brightness increase, decrease, or remain the same? Explain and support your answer with calculations
1. Four light bulbs, each with a resistance of 24002, are connected in parallel and plugged into a 120 volt outlet as shown below. (a) If any one of the bulbs was removed, what would happen to the remaining bulbs? (i.e., would the other bulbs remain lit?) Explain. b) If any one of the bulbs was removed, would the brightness of the remaining bulbs increase, decrease, or remain the same? Explain, and support your answer with calculations. PowE If all four bulbs were now connected in series, would their brightness increase, decrease, or remain the same? Explain, and support your answer with calculations. (c Outlet

Explanation / Answer

A Bulb lits, when some potential difference is applied across it's terminals. Brightness of Bulb depends upon value of this potential difference. More the potential difference, more is the brightness.

a) When Bulbs are connected in parallel, potential diffrence across each bulb is same and equal to 120 V outlet. If one of the bulb is removed, it does not change or effect the potential difference across remaing three bulbs. Hence remaining three bulbs remain lit.

b) Since potential difference across remaing bulbs remains same, that is 120V, brightness of remaining bulbs remains same. Power consumed by each of remaining bulbs,

P = V^2 / R = 60 W

c) When connected in series, outlet of 120V is equally divide across each bulb ( as resistance of bulbs are equal). Hence potential difference across each bulb is 120/4 = 30 V.

Power of each bulb is 30^2/240 = 3.75 W.

Hence brightness of bulbs decrease.

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