1)A car accelerates from 12 m/s to 17 m/s, what is the change n its momentum. Ma

Question

1)A car accelerates from 12 m/s to 17 m/s, what is the change n its momentum. Mass of the car is 845 kg.

2)A ball falls towards the ground at 9 m/s (downwards), and bounces up at 5 m/s (upwards). The mass of the ball is 166 gram. What is the change in momentum of the ball as it bounces (in kg.m/s).

3)A ball falls towards the ground at 8 m/s (downwards), and bounces up at 6 m/s (upwards). The mass of the ball is 268 gram. The collision with the ground occurs in a time duration of 32 ms (i.e. milliseconds). What is the Impulse from the ground.

4)A ball falls towards the ground at 8 m/s (downwards), and bounces up at 5 m/s (upwards). The mass of the ball is 292 gram. The collision with the ground occurs in a time duration of 20 ms (i.e. milliseconds). What is average force from the ground on the ball?

5)A toy car of mass 4 kg is moving at 6 m/s in the + X-direction. It hits a second toy car of mass 3 kg that is moving at 3 m/s in the + X-direction. They have a perfectly in-elastic collision (stick together). What is their speed?

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Explanation / Answer

1) m= 845Kgs

u = 12m/sec

v = 17m/sec

Change in momentum = m(v-u) = 845*(17-12) = 4225 Kg m/sec

2) m=166 gm = 0.166Kgs

u = -9m/sec

v = 5m/sec

Chane in momentum = m(v-u) =0.166* {(5-(-9)} = 2.324 Kg m/sec

3) m = 268 gm = 0.268Kg

u = -8m/sec

v=6m/sec

t = 32ms = 0.032sec

Impulse = m(v-u) = 0.268* {6-(-8)} = 3.752Kg m/sec

4) m = 292gm = 0.292Kg

u= -8m/sec

v = 5m/sec

t = 20ms

F = m(v-u)/t = 0.292* {5-(-8)}/0.020 = 189.8N

5)m1*u1+m2*u2 = (m1+m2)*V

V = (4*6 +3*3)/(4+3) = 4.714m/sec

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