1 . At high speeds, a particular automobile is capable of an acceleration of abo

Question

1 . At high speeds, a particular automobile is capable of an acceleration of about 0.520 m/s^2. At this rate, how long (in seconds) does it take to accelerate from 92.0 km/hr to 104 km/hr?

A kangaroo jumps to a vertical height of 267 cm. How long (in seconds) was the kangaroo in the air?

A motorcycle traveling 93.0 km/hr approaches a car traveling in the same direction at 88.0 km/hr. When the motorcycle is 55.0 m behind the car, the rider accelerates and passes the car 18.0 s later. What is the acceleration of the motorcycle (in meters/second^2)?

A 0.170 kg baseball, traveling 31.0 m/s, strikes the catcher's mitt, which recoils 17.0 cm in bringing the ball to rest. What was the average force (in newtons) applied by the ball to the mitt?

A wet bar of soap slides freely down a ramp 18.0 m long, inclined at 67.0 degrees. How long (in seconds) does it take to reach the bottom? (Neglect friction.)

A 7.0 kg object, moving with a constant velocity of 7.0 m/s, is acted upon by a force of 17 N in the direction of the motion for 5.0 s. What is the velocity (in meters/second) of the object at the end of this time?

8. How large a force (in newtons) is needed to accelerate a 2 metric-ton vehicle from rest to a speed of 30 km/hr in 8 s?

Explanation / Answer

1) u = 92 km/h = 92/3.6 m/s = 25.56 m/s

v = 104 km/h = 104/3.6 m/s = 28.89 m/s

a = 0.52 m/s2

Use:

v = u + at

=> t = (v-u)/a

= (28.89 – 25.56)/0.52

= 6.4s (ans)

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