1. Find the equivalent resistance of a 2 Ohm resistor connected in parallel to a
ID: 1865457 • Letter: 1
Question
1. Find the equivalent resistance of a 2 Ohm resistor connected in parallel to a series combination of 13 Ohm and 9 Ohm resistor.
2. You have a 1,600 W iron, operating at a potential difference of 170 V.
a. What is the resistance?
b. What is the current?
3. The power loss in a 60 km power line is 0.7 MW, if the 800 MW station pumps out electricity at a potential difference of 20,000 V.
a) What is the resitance of the power line?
b) What is the resistivity of the material if the diameter of the power lines is 25 mm.
Explanation / Answer
1.
Req= (2*13*9)/(2*13+13*9+2*9)= 1.453 ohm
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2.
Power=Vi
1600= 170*i
i= 9.41 A
a) R= V/i= 170/9.41= 18 ohm
b) i= 9.41 A
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3 (a)
P= V^2/R
R= 20000^2/(0.7*10^6)
R= 571.429 ohm
(b)
R= rho* L/A
571.429= rho* 60*10^3/(pi/4* (0.025)^2)
rho= 4.67*10^-6 ohm meter.
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