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(II) Extreme-sports enthusiasts have been known to jump off the top of El Capita

ID: 1865079 • Letter: #

Question

(II) Extreme-sports enthusiasts have been known to jump off the top of El Capitan, a sheer granite cliff of height 910 m in Yosemite National Park. Assume a jumper runs horizontally off the top of El Capitan with speed 4.0 m/s and enjoys a free fall until she is 150 m above the valley . (II) Three vectors are shown in Fig. 3-35. Their magnitudes floor, at which time she opens her parachute (Fig. 3-37). are given in arbitrary units. Determine the sum of the three (a) How long is the jumper in free fall? Ignore air resis- vectors. Give the resultant in terms of (a) components, tance. (b) It is important to be as far away from the clif (b) magnitude and angle with the +x axis. as possible before opening the parachute. How far from the cliff is this jumper when she opens her chute? 4.0 m/s 44.0) 56. A (A 28.0° FIGURE 3-35 Problems 9, 10, 11, 12, and 13 Vector magnitudes are given in arbitrary units ? (C-31.0) 10 m 150 m FIGURE 3-37 blem 26.

Explanation / Answer

1)

Given vectors are  

A = 44 cos28 i + 44 sin 28 j

B = 26.5 cos(180-56) i+ 26.5 sin(180-56) j

C = 31 cos 270 i + 31 sin 270 j

resultant vector is  

R = A+B+C

R = (Rx) i + Ry j

R = (Ax+Bx+Cx)i + (Ay+By +Cy) j

R = (44 cos28 + 26.5 cos(180-56)+31 cos 270)i + ((44 sin28 + 26.5 sin(180-56)+31 sin 270)) j

R = (38.85 -14.82 +0) i+(20.66+21.97-31)

R = (24.03) i + (11.63) j

the magnitude is  

R = sqrt(24.03^2+11.63^2) = 26.7

the direction is  

theta = arc tan (Ry/Rx)

= arc tan (11.63/24.03)

= 25.82 degrees

from +x axis

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2)

Given jumper initially at a height of h = 910 m

jumps horizontally with initial velocity ux = 4 m/s

opens paachute at 150 m from the floor

a) from equations of motions  

s = ut +0.5*a*t^2

y-y0 = v0y*t -0.5*g*t^2

y= y0 - v0y*t -0.5*g*t^2

here voy=0 m/s , y=h

h = y0-0.5*g*t^2

solving for t

t = sqrt(2(y0-h)/g)

substituting the values  

t = sqrt(2(910-150)/9.8)s

t = 12.454 s

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b) how far the jumper from the cliff before opening the parachute is  

V = x/t ==> x = v*t

here v is ux and t is time at which jumper opens the parachute

x = 4*12.454 m = 49.816 m