A ship’s compass is mistakenly placed 8.35 cm away from a wire carrying a curren

Question

A ship’s compass is mistakenly placed 8.35 cm away from a wire carrying a current of 8.25A. f) What is the strength of the wire’s magnetic field on the compass? Use the equation: ?? = ??°?? ?????? g) The strength of the Earth’s magnetic field is 5.20 x 10-5T. How far from the wire must the compass be mounted so that it only experiences a magnetic field of 5.20 x 10-7T (1/100 of the magnetic field of the earth) due to the wire? (3 points) Rearrange the equation to solve for R and fill in your new value for magnetic field.

Explanation / Answer

the equation for magnetic field due to current carrying wire is

B = uo I/ 2 pi R

= 4 pi * 10^-7 ( 8.25)/2 pi ( 8.35 * 10^-2)

=19.76 * 10^-6 T

(b)

B = uo I/ 2 pi R

R = uo I/ 2 pi B

= 4 pi * 10^-7 ( 8.25)/2 pi ( 5.2 * 10^-7)

=3.17 m

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