A flower pot is being held in an equilibrium position as shown in Figure using t
ID: 1863359 • Letter: A
Question
A flower pot is being held in an equilibrium position as shown in Figure using three cables OA, OB and OC. The weight of the flower pot is 300 N. Determine the following:
i. Position vectors for OA, OB and OC
ii. Write equilibrium equations in the x, y and z directions
iii. Find the tensions in cables OA, OB and OC
Explanation / Answer
i) OA = (8,0,0); OB =(-6,-5,5); OC =(0,8,5)
ii)
x-direction: T_oa-(6/root(86))*T_ob = 0 => T_oa - 0.647*T_ob = 0
y-direction: (-5/root(86))*T_ob+(8/root(89))*T_oc=0 => -0.539*T_ob + 0.848*T_oc = 0
z-direction: (5/root(86))*T_ob+(5/root(89))*T_oc=300 => 0.539*T_ob + 0.530*T_oc = 300
iii) tension in cables(solving ii)
T_oa = 221.6 N
T_ob = 342.5 N
T_oc = 217.7 N
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