I am very confused as I am doing the b20/n20 = 3/987 = .003 but I seem to be goi

Question

I am very confused as I am doing the b20/n20 = 3/987 = .003 but I seem to be going wrong somewhere. please help. All answers should be available from the nx values which are correct and copied from the graph.

Calculate fecundity for the x-10 age group of your cohort as follows 1. The number of female babies born between years 10 and 20-010- 10 2. The number of females who survived to year 10-n 10990 3. Fecundity for the 10-20 age class 22 10b1101 1000 750 500 250 Year 110 Enter this value in the m- column of the table for age class 10-20 second row) Using the same method, calculate fecundity for 20 and enter that 0 20 40 60 80 100 120 Year value in the third row of the table 01000 990 1.0 0.99 10 10 01 Q3.9. To check yourcalf what ismnn for this nonulation? 0.98 0.97 0.94 0.80 70 79 1077 0.58 0.21 0.033 30 978 That's not a good estimate for fecundity at age class 20. Check your math and try again 0.003 939 50 60 895 Check Answer 212 345 179 212 90 100 Number of births 12126 0.00

Explanation / Answer

Answer - At X=20   mx = 1-978/987 = 0.009

Age-specific fecundity (mx): the average number of female offspring a female has at age x.

           mx= 1-(nx+1/nx)

At X=0 mx = 1-990/1000 = 0.01

At X=10   mx = 1-987/990 = 0.003

At X=20   mx = 1-978/987 = 0.009

Age-specific survivorship(lx): the proportion of individuals in a cohort that survive from birth to age x.

lx = nx/n0

For X=0 lx = 1000/1000 = 1

X=10      lx = 990/1000 = 0.99

X=20      lx = 987/1000 = 0.987=0.99

and so on

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