A truck travels on a level roadway. After traveling initially at 65 mph, the bra

Question

A truck travels on a level roadway. After traveling initially at 65 mph, the brakes are applied so all tires are on the verge of skidding.

a)         A) If it takes 500 ft to come to a complete stop, what is the coefficient of static friction between the tires and the road?

b)             B) For the same scenario but on a 10

A truck travels on a level roadway. After traveling initially at 65 mph, the brakes are applied so all tires are on the verge of skidding. If it takes 500 ft to come to a complete stop, what is the coefficient of static friction between the tires and the road? For the same scenario but on a 10 degree downhill slope, what distance is required to come to a stop? Use the value of mu you calculated in part a.

Explanation / Answer

65 mph = 29.0576 m/sec

500 ft = 152.4 m

so... intial speed , u = 29.0576 m/sec

distance, s = 152.4 m

final velocuty , v = 0

lert the acceleraion be a ..

so.. v^2 = u^2 + 2*a*s

so.. 0 = 29.0576^2 + 2*a*152.4

so.. acceleraion a = -2.770157867 m/sec2

so.. mu * 9.8 = 2.770157866

so.. mu = 0.28267

b)

for 10 degree

acceelraion = 9.8 * ( sin 10 - 0.28267*cos 10 ) = -1.0263288128 m/sec2

so.. v^2 = u^2 +2*a*s

0 = 29.0576^2 - 2*1.0263288128*s

so.. distacne s = 411.3419146 m   = 1349.547 ft

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