The hoist shown below is operated by a motor driving a 4-threaded worm 1 that en
ID: 1862323 • Letter: T
Question
The hoist shown below is operated by a motor driving a 4-threaded worm 1 that engages a
100~tooth worm gear2. The worm gear is keyed to a shaft which also contains a 20-tooth spur
pinion 3. The pinion meshes with a 140-tooth spur gear4 mounted on the end of a 12 inch
diameter hoisting drum. Calculate the speed of hoisting (in feet-per-minute), lf the motor
operates at 600 rpm?
Explanation / Answer
the speed of hoisting v = (RPM) * (GR)* ( pi*D)
GR = speed reducer gear ratio = ((4* 200))/((140*4)+60) = 1.29
V = 600*1.29 * 3.14*12*0.0833 = 2429.99 feet / min.
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