The 30- lb block has an initial speed of vo = 12 ft/s when it is midway between
ID: 1861076 • Letter: T
Question
The 30- lb block has an initial speed of vo = 12 ft/s when it is midway between springs A
and B. After striking spring A (kA = 440 lb/ft), it rebounds and slides across the horizontal plane
and strikes spring B and then, rebounds and stops midway (i.e., back to the initial position).
Determine the total distance traveled by the block until it stops at the final position and the
stiffness kB of the spring B. The coefficient of kinetic friction between the plane and the block is
mk = 0.26. Neglect the size of the block.
Explanation / Answer
accn due to friction=-mug=0.26*32ft/s2
final velocity before hitting Ka V=sqrt(3.66^2-2*2.55*1.7*0.3)=10.75ft/s
maximum compression of Ka,0.5m*v^2=.5*kax^2+mu*mg*x; so, x=2.29
final velocity while leaving V2=sqrt(V^2-mu*g*2x); V2=2.54 m/s
net distance travelled for it to stop completely after release from ka=1.26m=4.13ft
data seems to be wrong it not doing the same
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