So, I found the solution to this problem on Chegg already, but without the figur

Question

So, I found the solution to this problem on Chegg already, but without the figure drawn and I mainly am wondering why their solution is correct. So, what I am hoping you guys can do is to draw the figure in the problem with all of the components of acceleration labeled on the figure and then maybe say why those are represented in that location, you don't need to solve it, after I see where each component belongs, I should be able to solve it myself. Thanks

Transposition between Coordinates For the instant shown the particle has a velocity v = 6 ft/sec in the direction shown and has acceleration components ax = 15 ft/sec2 and a theta = -15 ft/sec2. If the particle is 3 ft from the tracking station O, determine ar, ay, at,an ,and radius of curvature p of the path for this position. (Midterm #1, Spring 2013.) {Hint: Draw the related acceleration components of the total acceleration of the particle and take advantage of the simplified geometry for your calculations.) Ans. p= 2.078 ft

Explanation / Answer

See the image in the link

http://i.imgur.com/PDzJ2jU.jpg?1

Vr and Vtheta are the components along the polar cordinates at the given instant. Vx and Vy are ofcourse along the cartesian cordinates.

tangential cordinate is parallel to the direction of velocity and normal cordinate is perpendicular to it and points towards the center of curvature.

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