If you measured the time it takes for the construction elevator to go from A to

Question

If you measured the time it takes for the construction elevator to go from A to B, then ft to C. and then C to D. and you also know the distance between cach of the points, how could you determine the average velocity and average acceleration of the elevator as it ascends from A to D? Use numerical values to explain how this can be done If the sprinkler at A is 1 m from the ground. then necessary measurements from the photo to the approximate velocity of the water jet as it the nozzle of the sprinkler.

Explanation / Answer

This is simple. SEE

Suppose distance between each floor is 10 metres.

Time taken by elevator to reach subsequent floors will be same...i.e time taken by elevator to reach from A to B, or from B to C or From Cto D will be same..

Let it be t=10 seconds

But you have to calculate the time spent on each floor. let it be 20 seconds

So total time Taken by elevator to ascend from A to D= 3*time taken to reach each floor+ 3* time spent on each floor

                                                                                                          (since there are 3 stops in between A to D)

                                                                                              

                                                                                                 =3*(10+20)=90 seconds

Total distance covered= 10*3=30 metres

So avg velocity = 30/90= 1/3 m/s

avg acceleration can be calculated by NEwtons Law of motion as

v=u+at

u=0 (elevator starts from rest)

so

1/3=a*90

So

accleration=1/270 m/s^2

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