Full answers awarded full points See hydraulic lift system below, 10 mm rod and

Question

Full answers awarded full points

See hydraulic lift system below, 10 mm rod and 50 mm cylinder, to lift a 500 kg load. A handpump is being used with a stroke of 7 cm3 per pump actuation. How many pump cycles would be required to lift the load 100 mm high? Assume you operate the handpump at a speed of 0.3 Hz. How long would it take to lift the load 100 mm high? What is the work and power required from the pump operator? An electric motor is being used that pump at a rate of 3 litres / min. How long would it take to lift the load 100 mm? What is the work and power required from the electric motor?

Explanation / Answer

distance moved per actuation = 7 * 10 ^3 mm^3 / (pi*25^2) = 3.565 mm

so for rising through 100 mm , no of cycles required = 100/3.565 = 28.05

For 0.3 cycles, it takes 1 sec

so for 29cycles = 28.05 / 0.3 = 93.5 sec

work = F* displacement = 500*9.8 * 0.1 = 490 N

Power = work / time = 490/93.5 = 5.24 watt

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