FIND : The angle is 0.6248 I need a detailed FULL answer. A truncated cone shape

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FIND :

The angle is 0.6248
I need a detailed FULL answer.

A truncated cone shaped radiant heater is suspended in a very large enclosure as shown in the figure. The bottom surface (3) is open and exposed to enclosure at 300K while the top-heating surface (1) is kept at 1200K by electrical heating. The side-lateral surface (2) is made from an insulation-refractory material. Top-heating and side surfaces are diffuse and gray with eplision 1 = 0.9 and epsilon 2 = 0.8 respectively. Radiative heat transfer into enclosure q3 in (W), Temperature of the side (lateral) surface T2 in (K).

Explanation / Answer

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