(Solve equations by trial and error. Use a computer) An air foil of uniform chor

Question

(Solve equations by trial and error. Use a computer) An air foil of uniform chord is mounted vertically on a rail so that it can move in a single direction only. It is as if you had cut off a wing of an airplane and stood it up with its longer dimension in the vertical. There is no friction in the motion of the air foil. The only drag on the system is that produced by the drag coefficient of the airfoil. The setup angle is the angle between the airfoil reference plane and the normal to the direction of motion. In other words, if the rail is north-south, the airfoil faces east when the setup angle is zero and faces north when the setup angle is 90 degree. Consider the case when the setup angle is zero and the wind blows from the east. Since the wind generates a lift, the airfoil will move forwards. What speed does it attain? Conditions are STP. Area of the airfoil is 10 m2. Wind speed is 10 m/s. The coefficients of lift and drag are given by CL =0.6+ 0.066 alpha -0.001 alpha 2 -3.8 times 10-5 alpha 3 CD =1.2-1.lcos alpha

Explanation / Answer

good ques.

get lift force by bouyance eq.

and drag by friction

and solve .

I can do this but will post the solution in comments if you rate my ans first, wish is totally yours.

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