As preparation for the exam, look up or calculate the following information (giv
ID: 1855804 • Letter: A
Question
As preparation for the exam, look up or calculate the following information (give answers in Btu/lb): State the formula to calculate the constant pressure heat capacity of ethylene gas as a function of temperature: The constant pressure heat capacity of ethylene gas at 150 F, in Btu/lb: CP = [In this space show the plug-ins for the calculation of the value you report] The constant pressure heat capacity of ethylene gas at 200 F, in Btu/lb. CP = [don't show the calculations, just the value] The constant pressure heat capacity of ethylene gas at 500F, in Btu/lb: CP = [don't show the calculations, just the value] The constant pressure heat capacity of ethylene gas at 700F, in Btu/lb: CP = [don't show the calculations, just the value]Explanation / Answer
a) Cp = R(a + bT + cT^2 + dT^3 + eT^4) For ethylene, a = 1.426, b = 6.324*10^-3, c = 2.466*10^-6, d = -2.787*10^-9, e = 0.6429*10^-12 Thus, at T = 150 F = (150+460)R = 610 R and using R = 0.07 Btu/lb-R we get, Cp = 0.07*[1.426 + (6.324*10^-3)*610 + (2.466*10^-6)*610^2 - (2.787*10^-9)*610^3 + (0.6429*10^-12)*610^4] or Cp = 0.396 Btu/lbR b) Similarly , repeating above calculation for T = 200 F = (200+460)R = 660 R, we get Cp = 0.4196 Btu/lbR c) At T = 500 F = 500 + 460 R = 960R, we get Cp = 0.5495 Btu/lbR d) At T = 700 F = 700 + 460 R = 1160R, we get Cp = 0.6226 Btu/lbR
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