The image for this problem can be found through this link : http://imgur.com/afh

Question

The image for this problem can be found through this link : http://imgur.com/afhWBKK Please show all work/formulas so that I may understand this problem for the future. Thank you very much! :) An airplane is flying straight v= 18 ft/s^2, when it starts to climb along a circular path with a radius of curvature p = 1,900 ft. The airplane maintains v constant for about 30 seconds. Determine the acceleration of the airplane 25 seconds after the start of the climb and express the result in the Cartesian component system shown.

Explanation / Answer

acceleration = v^2/r
= 18 ft/s]^2/1,900 ft
= 0.17052 ft/s^2

distance travellerd in 25 s on the curve path
= 25 x 18 = 450 ft

circumference = 2 x 3.14 x 1900 = 11932

11932 equivalent to 360 degrees

so 450 will be 360/11932 x 450 =13.577 degrees from vertical

so the direction of accelration will be 13.577 degrees from vertival

and acceleration due to gravity acts vertically downward

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