Number of progeny D,S Parental phenotypes a, D,S×D,S b. D,S×D,L c, D,S × A,S D,L
ID: 185376 • Letter: N
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Number of progeny D,S Parental phenotypes a, D,S×D,S b. D,S×D,L c, D,S × A,S D,L A,S A, L 89 31 29 11 18 19 00 20 0 21 0 0 0 28 9 0 32 10 46 16 0 0 30 31 9 11 e. D,L×1, L g, D,S×D,L In dogs two independently sorting genes control coat color and length: dark (D) coat color is dominant over albino (A) and short (S) hair is dominant over long (L) hair. Use the symbols C and c for the dark and albino coat-color alleles and the symbols S and s for the short-hair and long-hair alleles, respectively. Assume homozygosity unless evidence indicates otherwise. What are the genotypes of the parents in cross c above?Explanation / Answer
The genotypes of the parents in cross _c_ above is C/c ; S/S X c/c ; S/S.
In cross _c_, there are no progenies having long (L) hair phenotype.This means, neither of the parents have the long (L) hair genes or 's' gene to transfer to their progenies. Both the parents have homozygous short (S) hair genotypes (S/S).
The genotypes of the parents in cross _b_ above is C/C ; S/s X C/C ; s/s.
In cross _b_, none of the progenies having albino (A) coat color phenotype.This means, neither of the parents have the albino (A) coat color genes or 'c' gene to transfer to their progenies. Both the parents have homozygous dominant dark (D) coat color genotypes (C/C).
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