Just need help on 11.156 of the satellite is equal to g(R/r)2, where g is the ac
ID: 1853468 • Letter: J
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Just need help on 11.156
of the satellite is equal to g(R/r)2, where g is the acceleration of gravity at the surface of the planet. R is the radius of the planet, and r is the distance from the center of the planet to the satellite. Determine the speed of a satellite relative to the indicated planet if the satellite is to travel indefinitely in a circular orbit 160 km above the surface of the planet. Venus: g = 8.53 m/s2, H = 6161 km. Knowing that the diameter of the sun is 864,000 mi and that the acceleration of gravity at its surface is 900 ft/s2, determine the radius of the orbit of the indicated planet around the sun assuming that the orbit is circular. (See information given in Prob s. 11.153-11.155.) Earth. (vmean)orbit = 66,600 mi/h For the race car of Prob. 11.167, it was found that it took 0.5 s for the car to travel from the position theta = 60 degree to the position theta = 35 degree . Knowing that b = 25 m, determine the average speed of the car during the 0.5-s interval.Explanation / Answer
GM/r^2=900ft we get mass of sun..where G is gravitational constant ans r is radius of sun for stable orbit..centrifugal force=centripetel force centrifugal=GMsunMe/r^2 centripetel=Me*v^2/r where r is the reqired radius and v is velocity of earth..(given) Me is mass of earth..equate both...we get r=GMsun/v^2 convert all units to SI
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