Water at 200 kPa and 10 degree celcius enters a mixing chamber at a rate of 150

Question

Water at 200 kPa and 10 degree celcius enters a mixing chamber at a rate of 150 kg/min where it is mixed steadily with steam entering at 200kPa and 150 degree celcius. The mix leaves the chamber at 200kPa and 70 dgree clecius, heat is lost to the surroundings at a rate of 190 Kj/min. Determine the rate of entropy generation during this process please help...im really confused on how to work this question out...should I calculate the net enthalpy change of the process?..im new to the concept of entropy...please help

Explanation / Answer

Scv = 0 = Q/T + mw_dot*s(Tm) + ms_dot*s(Ts) - mm_dot*s(Tm) + _gen

_gen = - { Qcv/Ta + mw_dot*[ sw(Tw,P) - sw(Tm,P)] + ms_dot*[ ss(Ts,P)- ss(Tm,P)] }

_gen = -Qcv/Ta - mw_dot*[ sw(Tw,P) - sw(Tm,P)] - ms_dot*[ ss(Ts,P)- ss(Tm,P)] }

Ta = 25 deg. C = 298 K

_gen = -(-)3.1667/298 - 2.5*[0.1510 - 0.9547] - 0.255*[ 7.2794- 0.9547] }

_gen = 2.01987651 - 1.6127985

_gen = 0.407 kW/K

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