Beam AB has rectangular cross section where point A is at the origin of the coor

Question

Beam AB has rectangular cross section where point A is at the origin of the coordinate system and point B has the coordinates B (1.2, -0.3, 2.4) m. The vector = (1 + 12 +1 )m is perpendicular to the axis AB of the beam, and is parallel to the thin dimension of the cross section The vector = (29.1 - 1.2 - 14.7 ) m is perpendicular to both the axis AB of the beam and to . The force applied to point B of the beam has the direction angles Theta x = 144 degree , Theta y = 72 degree , and Theta z = 60 degree . If the magnitude of is 1000N. determine the moment of this force about , and .

Explanation / Answer

Use this formula. M = F x d , m-moment, F-force, d -distance Note: All forces must be parallel in either direction (opposite or same direction) and must be perpendicular to the body. Body means material under analysis. ie. beam, column, etc. http://physics.csustan.edu/Marvin/heatlightsound/Summaries/Machines/simple_machines.htm

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