Tired of watering his garden, your instructor is attempting to grow desert plant

Question

Tired of watering his garden, your instructor is attempting to grow desert plants. One such plant is Indian paintbrush. A yellow variant has shown up, and we would like to determine if this variant is a Mendelian trait. We have taken a pure breeding red plant and crossed it with a a pure breeding yellow plant. The resulting F1 plants were selfed and the F2 data is presented below:

Red Flowers 207

Yellow Flowers 67

Perform a chi square analysis on this data using the following hypothesis:

The mode of inheritance for flower color in Indian paintbrush plants is simple Mendelian.

What is the calculated chi-square value? Round to three decimal places.

Explanation / Answer

Answer:

Based on the F2 phenotypic ratio, red color may be considered as the dominant phenotype and yellow color may be considered as recessive phenotype. The expected F2 phenotypic ratio of monohybrid cross is 3/4 (dominant phenotype) : 1/4 (recessive phenotype).

Chi-Square value = 0.044

Phenotype Observed(O) Expected (E) O-E (O-E)2 (O-E)2/E Red 207 205.5 1.5 2.25 0.01 Yellow 67 68.5 -1.5 2.25 0.03 274 274 0.044

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