In a rigid tank, water is heated by a Benson burner while being stirred by a pad

Question

In a rigid tank, water is heated by a Benson burner while being stirred by a paddle wheel for better mixing of the water. Initially, the internal energy of the water is 800 kJ. During a heating process of the Benson burner, the paddle wheel does 100 kJ of work (mechanical energy) during the stirring while 200 kJ of thermal energy (heat) is dissipated from water to the surrounding. At the final state, the internal energy of water is 1400 kJ. Please find: Is the volume of this rigid tank going to change during the heating process? Is this system a closed system or control volume system and explain why List the forms of energy transfer involved in this system (3) The heat transferred from the Benson burner to water during this process? (Tips: Use first law of thermodynamics)

Explanation / Answer

1.YES THE VOLUME OF RIGID TANK WILL CHANGE AS THE TEMPERATURE OF TANK WILL CHANGE. 2.CLOSED SYSTEM AS THERE IS TRANSFER OF HEAT AND WORK 3.HERE CONDUCTION TAKES PLACE FOR HEATING TANK, CONVECTION FOR HEATING WATER AND RADIATION FROM SURFACE. 4.INTERNAL ENERGY OF WATER WITHOUT BUNSEN HEATING SHOULD BE 800+100-200=700KJ BUT IT IS 1400KJ MEANS (1400-700)KJ HAS BEEN TRANSFERRED FROM BURNER

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