1. For the circuit shown in Fig. 1, let 2. Determine the generic (in terms of R

ID: 1846974 • Letter: 1

Question

1. For the circuit shown in Fig. 1, let

2. Determine the generic (in terms of R and C) capacitor-voltage step response for

the circuit when the input signal jumps from 0 V to 5 V.

3. Determine the generic (in terms of R and C) capacitor-voltage natural response

for the circuit when the 5 V input signal drops to zero.

4. Let R = 47 k-ohms, and C = 0.022 micro-F. Determine the circuit time constant. Then,

use the time constant to calculate the frequency of the square wave that is needed

to allow the network to reach equilibrium after application of a step and then have

its natural response reach equilibrium before application of the next step.

5. Repeat Step 4 using R =18 k-ohms

6. Repeat Step 4 using R =120 k-ohms

Thanks in advance for any help!!!

1) Vs(t) = 5u(t) V

Vs(s) = 5/s

2) Vc(0-)=0 V

so Vc(0+) = 0 V.

3) Vc(t-) = 5V

Vc(t+) = 5V

4) time constant = RC = 1.034 ms

w = 1/RC = 967.1

f = w/2pi =153.9 Hz

5) time constant = RC = 0.396 ms

w = 1/RC = 2525.25

f = w/2pi =401.9 Hz

6) time constant = RC = 2.64 ms

w = 1/RC = 378.8

f = w/2pi =60.3 Hz

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