it is physics Problem 3: A liquid with a specific gravity of 0.85 is contained i
ID: 1845691 • Letter: I
Question
it is physics
Problem 3: A liquid with a specific gravity of 0.85 is contained in an open tank 8 feet in diameter and 10 feet tall. What should be the range be for a pressure gage to be placed at the base of the tank?
Problem 5: A displacer is 10 inches in diameter and 40 inches long. If it is half submerged in a liquid with a specific gravity of 0.9, what is the buoyant force acting in it?
Problem 7: If a column of liquid 15 feet high causes a force of 140 lbs on a circular area with a 5" diameter, what is the specific gravity of the liquid?
Problem 14: A horizontal pipe decreases from an inside diameter of 4 inches to 2 inches. If the pressure in the 4 inch section is 100 psi and 400 gallons per minute of water are flowing, what is the pressure in the 2 inch section?
Problem 18: Seawater with a specific weight of 64.0 lbs/ft^3 is at a level of 4 feet above the centerline of the exit pipe. The tank is closed at the top and there is a pressure of 1 psig above the seawater. What is the velocity at the end of the pipe?
A liquid with a specific gravity of 0.85 is contained in an open tank 8 feet in diameter and 10 feet tall. What should be the range be for a pressure gage to be placed at the base of the tank? A displacer is 10 inches in diameter and 40 inches long. If it is half submerged in a liquid with a specific gravity of 0.9, what is the buoyant force acting in it? If a column of liquid 15 feet high causes a force of 140 lbs on a circular area with a 5" diameter, what is the specific gravity of the liquid? A horizontal pipe decreases from an inside diameter of 4 inches to 2 inches. If the pressure in the 4 inch section is 100 psi and 400 gallons per minute of water are flowing, what is the pressure in the 2 inch section? Seawater with a specific weight of 64.0 lbs/ft^3 is at a level of 4 feet above the centerline of the exit pipe. The tank is closed at the top and there is a pressure of 1 psig above the seawater. What is the velocity at the end of the pipe?Explanation / Answer
3) S = specfic gravity =0.85
d = density of liqiud = 1000*0.85 = 850 kg/m^3
h =height of tank =10 feet = 10*0.3 m = 3 m
g = acceleration due to garvity =9.8 m/s^2
po = atmospheric preccure = 101325 Pa
P = pressure at the bottm
= Po + dgh
= 101325 Pa + 24990 pascal
=126315 pa
range is Po to P = 101325 to 126315 pa
5)
V = volume = pi*(5)^2*40 inch^3 = 3140 inch^3 = 0.049 m^3
d - density liquid = 900 kg/m^3
buoyant force = dV*g = 432.73 N
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.