The 3.25kg collar shown below is attached to a spring and released from rest at
ID: 1844328 • Letter: T
Question
The 3.25kg collar shown below is attached to a spring and released from rest at A. The collar then travels downward a distance of y = 1.90m . The spring has a spring constant of k = 25.5N/m . The distance a is given as 1.10m . The datum for gravitational potential energy is set at the horizontal line through A and B.
Determine the magnitude of the average friction force exerted on the collar when the velocity of the collar at C is 3.59m/s and the spring has an unstretched length of 0.65m .
Express your answer to three significant figures and include the appropriate units.
The 3.25kg collar shown below is attached to a spring and released from rest at A. The collar then travels downward a distance of y = 1.90m . The spring has a spring constant of k = 25.5N/m . The distance a is given as 1.10m . The datum for gravitational potential energy is set at the horizontal line through A and B. Determine the magnitude of the average friction force exerted on the collar when the velocity of the collar at C is 3.59m/s and the spring has an unstretched length of 0.65m . Express your answer to three significant figures and include the appropriate units.Explanation / Answer
It is simply using energy conservation, change in energy = frictional energy
or
mgy - 1/2 mv2 -1/2 kx2 = frictional energy
frictional energy = 3.25*10*1.9 - 0.5*3.25*3.592 - 0.5*25.5*(1.54544984001001492- .452)
= 12.9364185981659966971 J
=> frictional force = energy / distance = 12.9364185981659966971/1.9
= 6.8086413674557877353158N
avg. frictional force = 6.809 N
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