An expensive level transmitter (installed at the bottom of tank) has failed and

Question

An expensive level transmitter (installed at the bottom of tank) has failed and the plant does not have a spare. The instrument tech tells you that the department has several pressure gauges that could be used as a substitute until the replacement level transmitter arrives If the maximum tank height is 360 inches and the specific gravity of the fluid is 0.85 calculate the max pressure reading a replacement pressure gauge must display for this application. You may assume the tank is vented to the atmosphere

Explanation / Answer

The specific gravity of the fluid is given = 0.85

Therefore,

The density of the fluid = density of water x specific gravity of the fluid

The density of the fluid = 1000 x 0.85 = 850 Kg/ m^3

Now , the pressure exerted by the fluid that will be recorded by the Pressure guage = Density of the fluid x depth x acceleration due to gravity = p x h x g

Now , depth h = 360 in. = 360 x 0.0254 m = 9.144 m

Therefore,

the pressure exerted by the fluid that will be recorded by the Pressure guage = 9.8 x 9.144 x 850

= 76169.52 Pa = 76169.52 x 10-5 bar = 0.76169 bar ........................................... Ans.

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