The forces shown below are perpendicular to plane ABC. Points D, E, and H lie on

Question

The forces shown below are perpendicular to plane ABC. Points D, E, and H lie on plane ABC. F_1 = 25 N, F_2 = 15 N, and F_3 = 20 N. Express the forces in vector form. Replace the system shown below with an equivalent system consisting of a single force and couple moment at point C. Determine the moment generated by the three forces about line BC (magnitude only). Can the equivalent system from part B be replaced by a single force? If so, determine the location on plane ABC (15x + 12y + 20z = 60) where the force should be located. If not, determine the angle between the single resultant force and couple moment at C.

Explanation / Answer

ans(a) F1=0i+0j+25k

F2=0i+0j+15k

F3=0i+0j+20k

ans-(b) since all the forces are acting in the same direction so the equilent forces will act in the -z axis direction whose value will be

F=F1+ F2+F3

F=60

and there will equivalent moment=M

M=F1*7+F2*1+F3*2.5

M=25*7+15*1+20*2.5

M=240 N m

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