The process of passing air through an adiabatic throttling valve neglecting chan
ID: 1842408 • Letter: T
Question
The process of passing air through an adiabatic throttling valve neglecting change in kinetic and potential energies is: an isothermal process an isenthalpic process an isentropic process answers "a" and "c" are correct Choose the correct statement. The relation delta te = C_v, ave delta T in an ideal gas is not restricted to constant volume processes only. The process in a container which has only one inlet without any outlet, cannot be a steady process. The boundary work associated with an expanding close system is always positive All of the above statements are correct Choose the correct statement Carnot cycle is an impossible cycle because entropy decreases during one of its processes All Isentropic processes are reversible All reversible processes are isentropic It a not possible to absorb heat during an isentropic process Determine the entropy of R-134a with the pressure of 50 psia pressure and enthalpy of 95btu/lbm 0.41125 Btu/lbm.R 0.05413 Btu/lbm. R 0. 19425 Btu/lbm. R 0.14025 Btu/lbm.R An Engine absorbs 500 kJ of heat from a thermal reservoir at 227 degree C. The entropy change (S_2-S_1) of the thermal reservoir in this process is: -1 kJ/kg 2.2 kJ/kg -2.2 kJ/kg 1 kJ/kgExplanation / Answer
Q 1- Ans
A throttling process is defined as a process in which there is no change in enthalpy and no work is done. so process will be isoenthalpic. Also due to motion of fluid there will be some heat loss so process will not be isothermal in real case. so correct answer is C.
Q 2 Ans-
(a) The relation is restricted to constant volume proccess only.
(b) The process may be steady. Assume the case of water entering in hot container and same amount water (as at inlet)is being vaporized.
(c) Boundary work associated with an expanding close system is always positive as the vinal volume increases.
So, correct answer is C.
Q 3 Ans-
(d) All reversible adiabatic processes are necessarily isoentropic.
As,
ds = dqrev / T
for an isoentropic process, the ds will become zero only when dqrev become zero. so heat can't be absorbed.
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