Problem 10-57, only use the alloy corresponding to a 72wt% FeO composition. For

Question

Problem 10-57, only use the alloy corresponding to a 72wt% FeO composition. For problem (g), use 1680 C instead of 1600 C.

3000 2000 S- (Mg, Fe)O 1000 Mgo 20 40 60 80 Feo Weight percent FeO Figure 10-21 The equilibrium phase diagram for the Mgo-Feo system. The dotted curve shows the nonequilibrium solidus. (For Problems 10-3 10-36, 10-44, 10-45, 10 53, 10-57, and 10-63.) 10-57 For equilibrium conditions and a Mgo-65 wt% FeO ceramic, determine (a) the liq- uidus temperature; (b) the solidus temper- ature, (c) the freezing range; (d) the composition of the first solid to form dur- ing solidification; (e) the composition of the last liquid to solidify, (f the phase(s) present, the composition of the phase(s), and the amount of the phase(s) at 1800°C; and (g) the phase(s) present, the composi- tion of the phase(s), and the amount of the phase(s) at 1600°C. (See Figure 10-21.)

Explanation / Answer

>> Using FeO coposition of 72 %,

From Diagram, at 72 %, drawing a vertical line to intersect the graph

>> From This we get

a). Liquidus temperature = 1850 C

b). Liquidus Temperature = 1560 C

c) Freezing Range = 1850 - 1560 = 290 C

d). During Solidification from 1850 C, solid starts forming.

Drawing a horizontal tie line, which intersects at two points: at 78 % & at 52 %

SO, Using tie line concept,

Solid Composition = (78 - 72)/(78 - 52) = 0.23 = 23% ......ANSWER........

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