1) If the index of refraction of the surroundings is greater than the index of r
ID: 1837458 • Letter: 1
Question
1) If the index of refraction of the surroundings is greater than the index of refraction of the lens, a concave lens will: be negative/positive power and converge/diverge light ?
2) In a flashlight a concave mirror is used to create a beam of light with parallel rays. Where should the light source be placed?
3) Calculate the index of refraction for an object which light travels 1.97 x 108 ms^-1 ?
4) If R1 is greater than R2, and both positive values in the lens makers equation, a glass lens in the air will: be negative/positive power and converge/diverge light ?
Explanation / Answer
Answer:
(a) positive power and converge the light
(b) Flash must be on a focus of mirror
(c) refractive index = speed of light in vacuum/ speed of light in medium
refractive index = 3 x 108 / 1.97 x 108 = 1.52
(d) 1/F = (n -1) (1/R1 - 1/R2)
if R1 > R2 then F remains positive
means lens will be of positive power and converging
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.