What is the energy stored in the capacitor? 1 times 10^-6 J 2 times 10^-6 J 4 ti

Question

What is the energy stored in the capacitor? 1 times 10^-6 J 2 times 10^-6 J 4 times 10^-6 J 8 times 10^-6 J If the distance between the plate on the capacitor were doubled, the energy stored in the capacitor would: 2 times 10^-6 J 4 times 10^-6 J 8 times 10^-6 J 16 times 10^-6 J If the area of the plates on the capacitor were doubled, the energy stored in the capacitor would: 2 times 10^-6 J 4 times 10^-6 J 8 times 10^-6 J 16 times 10^-6 J If the area of the plates on the capacitor were doubled, the voltage across the capacitor would: Decrease by a factor of 2. Remain the same. Increase by a factor of 2. Increase by a factor of 4.

Explanation / Answer

17. energy will stored in capacitor until current through capacitors becomes zero.

in this case.

current through 2ohm = 5 / (3 + 2) = 1 A

PD across capacitor = 2 * 1 = 2 volt

energy stored = C V^2 /2 = (2 x 10^-6) (2^2) /2

= 4 x 10^-6 J

Ans(C)

18. C = e0 A / d

d is doubeld so C will be halved so energy .

energy = 2 x 10^-6 J

Ans(A)

19. A is doubled then C also doubled so energy ,

energy = 8 x 10^-6 J

Ans(C)

20. Voltage is independent of capacitance.

hence V will remain same.

ans(B)

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