m points below the principal axis (it is inverted) and is 0.160 m in front of a
ID: 1836071 • Letter: M
Question
m points below the principal axis (it is inverted) and is 0.160 m in front of a diverging lens. The focal length of the lens is 0.31 m. (Include the sign of the value in your answers.) (a) What is the magnification?(b) What is the image height?
m
(c) What is the image distance?
m m points below the principal axis (it is inverted) and is 0.160 m in front of a diverging lens. The focal length of the lens is 0.31 m. (Include the sign of the value in your answers.) (a) What is the magnification?
(b) What is the image height?
m
(c) What is the image distance?
m 0.31 (a) What is the magnification?
(b) What is the image height?
m
(c) What is the image distance?
m
Explanation / Answer
(c) 1/v - 1/u = 1/f => 1/v + 1/16 = -1/31 => 1/v = -(1/16 +1/31) => v = - 10.55 cm
(a) magnification, m = v/u = 0.6596
(b) image height = m x (height of object)
height of object is missing in question.
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