1) A battery consists of a 12V battery connected to three resistors (25,30, and
ID: 1835983 • Letter: 1
Question
1) A battery consists of a 12V battery connected to three resistors (25,30, and 35 Ohms). Calculate A. The equivalent of the series circuit B. The current across each resistor.2) If the three resistors in problem #1 are connected in parrallel, calculate A. The equivalent resistance B. The current across each resistor.
1) A battery consists of a 12V battery connected to three resistors (25,30, and 35 Ohms). Calculate A. The equivalent of the series circuit B. The current across each resistor.
2) If the three resistors in problem #1 are connected in parrallel, calculate A. The equivalent resistance B. The current across each resistor.
A. The equivalent of the series circuit B. The current across each resistor.
2) If the three resistors in problem #1 are connected in parrallel, calculate A. The equivalent resistance B. The current across each resistor.
Explanation / Answer
(1).Emf of the battery E = 12 V
Resistances R = 25 ohm
R ' = 30 ohm
R " = 35 ohm
Three are in series.So, equivalent resistance Req = R + R ' + R "
Req = 25 ohm + 30 ohm + 35 ohm
=90 ohm
(B). Current across each resistor i = E / Req Since in series circuit the current is same in all resistors
= 12 / 90
= 0.13333 A
(2) In parallel combination ,
(1/Req) =(1/R ) +(1/R ') +(1/R ")
=(1/25) +(1/30)+(1/35)
= 0.1019
Req = 1/0.1019
= 9.813 ohm
Current in circuit i = E / Req
= 12 / 9.813 = 1.2228 A
(B). ratio of currents in R,R ',R " are = (1/R) :(1/R ') :(1/R ")
=(1/25):(1/30):(1/35)
= (1050/25):(1050/30):(1050/35)
=42 : 35 : 30
So, current in R is = i [ 42 /(42+35+30)]
= 1.2228 [ 42 /107]
= 0.48 A
current in R ' is = i [ 35 /(42+35+30)]
= 1.2228 [ 35 /107]
= 0.4 A
current in R " is = i [ 30 /(42+35+30)]
= 1.2228 [ 30 /107]
= 0.3428 A
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