Write a function printBinary() that displays the number of bits used VB2010. Usi

Question

Write a function printBinary() that displays the number of bits used VB2010. Using 'sizeof()' if the user enters and int 17 the function should display 000000000000000000000000000010001.
1- Initialize and unsigned int variable mask, with a value whose binary representation has a 1 followed by zeros.
2- For a counter running from 1 thru the number of bits
a. If the bitwise-and (&) of the given integer and mask is non zero: Display 1
Else Display 0
b. Shift the bits in mask one position to the right using >>.

Explanation / Answer

#include <iostream>

using namespace std;

char * printBinary (unsigned int val, char *buff, int sz) {

char *pbuff = buff;

/* Must be able to store one character at least. */

if (sz < 1) return NULL;

/* Special case for zero to ensure some output. */

if (val == 0) {

*pbuff++ = '0';

*pbuff = '';

return buff;

}

/* Work from the end of the buffer back. */

pbuff += sz;

*pbuff-- = '';

/* For each bit (going backwards) store character. */

while (val != 0) {

if (sz-- == 0) return NULL;

*pbuff-- = ((val & 1) == 1) ? '1' : '0';

/* Get next bit. */

val >>= 1;

}

return pbuff+1;

}

#define SZ 32

int main(int argc, char *argv[]) {

int i;

int n;

char buff[SZ+1];

n = 17;

cout<<" " << n <<" -> "<< printBinary(n,buff,SZ)<<endl;

return 0;

}

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