Hello, I would like to go over the transient states of a LRC circuit, starting f
ID: 1832519 • Letter: H
Question
Hello,
I would like to go over the transient states of a LRC circuit, starting from under damped, to critical damped, and finally over damped. I am familiar with the characteristics themselves. What I am seeking is the mathematical model as the LRC goes into these different states (when is changed for each impulse).
When the circuit becomes critically damped where 0= , then = 0. The circuit no longer oscillates, and the above equation doesn't hold. Peak amplitude is achieved, with the response reaching stable state the quickes. How would I model this mathematically?
When the circuit becomes over damped where > 0, then becomes imaginary. I remember an explanation using the above current equation, that the sin becomes hyperbolic. Could someone elaborate on this, show me how this is express mathmatically?
Thanks!
Explanation / Answer
The equations in my text book slightly differ from yours, however, it looks as if they are essentially the same thing but instead of , is used:
Over damped:
When the characteristic equation for the circuit has real and distinct roots, i.e.
s2-s-12=(s+3)(s-4)
Equation for this state is:
x(t) = K1Aes1t+K2es2t
x(0+)=K1 + K2
x'(0+) = s1K1 + s2K2
Under damped:
where wo > where =R/(2L) when in series and =1/(2RC) when in parallel
x(t) = (A*cos(wdt) + B*sin(wdt))e-t
x(0+) = A
x'(0+) = -A + wdB
Critically damped:
where wo= and roots are equal; s1=s2
x(t) = (K1 + K2t)es1t
x(0+) = K1
x'(0+) = s1K1 + K2
wd = (wo2-2)
wo = 1/(LC)
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